Tom wants to catch a hare. He is standing 250 yards south from the hare. The hare starts moving due east. Tom, instead of moving in the northeast direction, moves in such a way that at every instant, he is going towards the hare. If speed of Tom is one and one-third times that of the hare, find the distance each traveled before he caught the hare.

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Deepak kumar Behera

  • Jul 12th, 2006
 

  The hare starts from let point A. Let Tom stands at B which is 250m away  

  from A .Suppose they meet each other at point C. So joining A,B,C we get

  perpendicular triangle.Now AB = 250yard, AC = s(assume distance covered by hare), BC= (3+1/3)s

Now applying the formulae

     s^2 + 250^2 = (3 + 1/3) ^2

    s= 600/{ (91)^(1/2) } i.e distance covered by hare

   Distance covered by  Tom = (3+1/3)s

Debarghya

  • Sep 13th, 2006
 

Well the answer provided was not correct.

Lets have a look at the scenario:  

according to the scenario the boy will take a CURVE not a straight line.

so using Pythagoras Theoram wont help.

In this case we get a curve with two tangents( X and Y axes) intersectin

at 90 degrees.If we draw two perpendicular lines from those tangents,they meet at a point which is the center of a circle and the path taken by the boy is the ARC.

Thus we get an ARC with 90 degrees at the center and radius is 250 feet or meters(because it forms a suare !)

Thus the lenght of the arc is: 2*pi*radius* (90/360)

                                         2* (22/ 7)*250 = 250*11/7= 392.85.

Thus the answer is 392.85.

                       

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lux

  • Dec 3rd, 2006
 

i wonder how you took the distance travelled as  3+ 1/3

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lux

  • Dec 3rd, 2006
 

the path taken could be parabolic.

y^2=2ac

250^2=2*s*4/3s

s=153.09

s is the distance travelled by hare,4/3s=204.12

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