I think there is no way to define the same method twise..

Consider this as example...

interface Interface1
{
int method();
}

interface Interface2
{
int method();
}

public class Question1 implements Interface1 Interface2
{
public int method()
{
System.out.println( From implemented method()... );
return 0;
}

public static void main(String[] args)
{
Question1 obj new Question1();
obj.method();
}
}

But if you find that we can do it in any other way please let me know...!

yes

i posted the question and forgot to see it. but now i will try bye real program and post it.

ok

yes

you are correct there is no way to define the method twice. and it doesnt matter which method we define because we want the method with that name and the compiler dont bother about in which interface it comes from it checks only that the method is defined or not. am i correct?

interface Interface1
{
int method();
}

interface Interface2
{
int method();
}

public class Question1 implements Interface1 Interface2
{
public int method()
{
System.out.println( From implemented method()... );
return 0;
}

public static void main(String[] args)
{
Question1 obj new Question1();
obj.method();
}
}

Hi pansi This will work fine. It daisplay's the result.

. For example

interface Interface1
{
int method();
}
interface Interface2
{
int method();
}
class Question1 implements Interface1 Interface2
{
public int method()
{
System.out.println( From implemented method()... );
return 0;
}
public static void main(String[] args)
{
Question1 obj new Question1();
obj.method();
}
}

This will run fine and the following result it will display ..
output :
From implemented method()...

If it contains same method with different signatures. Then it will give compile time error.

For example

interface Interface1
{
int method();
}
interface Interface2
{
int method();
}
class Question1 implements Interface1 Interface2
{
public int method()
{
System.out.println( From implemented method()... );
return 0;
}
public static void main(String[] args)
{
Question1 obj new Question1();
obj.method();
}
}

Output:

Question1.java:14: method() in Question1 cannot implement method() in Interface2

; attempting to use incompatible return type

found : int

required: float

public int method()

^

1 error

yes u can do it with no problem

by using anonymous classes u can implement this.

I am writing the code to ur problem.

interface int1{
int meth1();
}

interface int22{
int meth1();
}

public class Applic implements int1 int22

{

public int meth1(){

System.out.println( this is the method present in int1 interface implemented class; );

return 5;

}

// it is the one of the Syntax if u want to create a object to a class that extending int 22 interface.

static int22 i22 new int22(){

public int meth1()

{

System.out.println( this is the method developed in int 22 );

return 6;

}

};

public static void main(String args[])

{

i22.meth1();//it calls the meth1 present in interface int22 implemented class.

Applic c new Applic();

c.meth1();

}

I hope this is the right answer u have know better than this pls post