There is 2 namely emp, dept emp contains empid,ename,deptno dept contains depid,deptno deptno is primary and deptno in emp is foreign keyMy question is no of employees working in particular department . The display should show departname and no of employees in particular department.Please answer to my email id

Interview Candidate
Jan 20th, 2006
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Showing Answers 1 - 3 of 3 Answers

Laxmi Prasanna.Nedunuri

Jan 27th, 2006

select dept.depid, count(emp.empid) from dept, emp where dept.deptno = emp.deptno group by dept.deptid
considering depid is department .

madhu

Feb 23rd, 2006

the query is
select d.dname,count(*)
from emp e, dept d
where e.deptno = d.deptno
group by d.dname

durga4578
Profile Answers by durga4578 Questions by durga4578

Mar 11th, 2006

select count(empid),d.deptname from emp, dept d where d.deptno=emp.deptno group by deptno