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There is 2 namely emp, dept
emp contains empid,ename,deptno
dept contains depid,deptno deptno is primary and deptno in emp is foreign key
My question is no of employees working in particular department . The display should show departname and no of employees in particular department.
Please answer to my email id

Asked by: Interview Candidate | Asked on: Jan 20th, 2006
Showing Answers 1 - 3 of 3 Answers
Laxmi Prasanna.Nedunuri

Answered On : Jan 27th, 2006

select dept.depid, count(emp.empid) from dept, emp where dept.deptno = emp.deptno group by dept.deptid

considering depid is department .

  
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madhu

Answered On : Feb 23rd, 2006

the query is

select d.dname,count(*)

from emp e, dept d

where e.deptno = d.deptno

group by d.dname

  
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durga4578

Answered On : Mar 11th, 2006

View all questions by durga4578   View all answers by durga4578

select count(empid),d.deptname from emp, dept d where d.deptno=emp.deptno group by deptno

  
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