I don't think the compiler would compile this without errors. What is f and what value would m take? that is just random.

And n m++ is not assignment too. Its just logical comparison.

Please correct me if i am wrong.

Thanks

hi

n m++ is not an assingment but it is a logical comparision.

int n f m;

int n m++; // in this statement m is incremented to m+1//

int m ++n; // in this statement n is incremented to f+1//

print(n m);

ans: (f+1 m+1)

Hi

Here f should ' f ' o/w compiler will give error as it will be considered as a variable........ it will assign the ASCII value of 'f ' to n i.e. 102 ......... then the values of m and n will be incremented by 1 so the output should be ................ 103 1

i guess there are many problems in the question above first that f is not declared b4 and is directly assigned to n

and nxt the printf statement is given as print so we may come acrooss these two prob and hence this may not work

first of all we cannot assign two value to the same variable as given n f m

the error occurs there itself so it results in compilation error