All the children were arranged in rows. All the rows containing equal number of students.
If 4 students were removed from each row 10 more rows had to be added. If 5 students
were added in each row number of rows were reduced by 8. Find the number of children.
RE: All the children were arranged in rows. All the ro...
Question: All the children were arranged in rows. All the rows containing equal number of students. If 4 students were removed from each row 10 more rows had to be added. If 5 students were added in each row number of rows were reduced by 8. Find the number of children
RE: All the children were arranged in rows. All the ro...
Lets assume we have X Col and Y rows. So now total childrenwill be XY. so we have two equations here 1. (x-4)(y+10) and (x+5)(y-8) and both are equal. as the number of children are same. So if equate these eqns. we get y 2x. now substitute each of options eg. xy 800 and then substuting y 2x we get 2x to the power 2 800 which means x 20 and y 40.For all pther options we dot get exact square root.
RE: All the children were arranged in rows. All the ro...
Adding on to what infor said above. there are two equations (x-4)(y+10) xy and (x+5)(y-8) xy. The simplified form of these two equations are 10x-4y 40 and 8x-5y -40. Solving these two equations we get x 20 and y 40.So therefore the no of students are xy(20*40) ie 800(D).
