For the following C program:swap(int x, int y){ int temp;temp=x;x=y;y=temp;}main(){int x=2;y=3;swap(x,y);}After calling swap, what are the values x & y?

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Sachin Chakote

  • Jul 22nd, 2005
 

The values of x and y will be same since there scope is local the swapping done inside swap() function is not reflected inside main(). 
 

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shanmugam

  • Jul 25th, 2005
 

x=2 
y=3

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vaseef

  • Nov 10th, 2006
 

here the question it self has syntax error.swap (int x, int y) is required.. in question swap(int x,y) is given.If we correct the line and execute the pgm , the values will not be swapped in main().so values will be x=2;y=3;

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KALAI

  • Jan 27th, 2007
 

answerthe value of x and y will be d same because the swap() doesn't have a return statement.......

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ramyashreebharadwaj

  • Feb 7th, 2008
 

here the value of x=2 and y=3...as in it does not change because here only the values are passed as arguments....for the values to get changed a referece to the variables  has to be passes as an argument

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