Amit Dhamija

• Aug 15th, 2005

 

ans. 2

chaitanya

• Nov 9th, 2006

 

How the answer is 2. Since there are 3 independent paths if u c if am not wrong.

abhi_dendrite

• Dec 6th, 2006

 

The program begins with a conditional statement if (x==0) ||( y==0)...therefore it gives rise to 2 paths

Lets take a dry run...

lets say a) x=1,y=0; b) x=0 & y=0; c) x=0,y=1; d) x=1,y=1

condition a returns true

condition b returns true

condition c returns true

condition d returns false

Therefore there are actually 2 possibilities hence 2 paths two individual paths for the code..There cannot be any other possibility..

Also if we do a flowchart E=2; N=2 and cyclomatic complexity E-N+2=2

If I am wrong please enlighten me abhi_dendrite