A works thrice as much as B. If A takes 60 days less than B to do a work then find the number of days it would take to complete the work if both work together?

22� days

Interview Candidate
Jun 4th, 2005
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rekha

Oct 13th, 2006

As the efficiency of doing work is 1:3 the days required are less for A.so propotion will be x : 3x = y-60 : yafter solving xy=90 sp y = 90/xfor A , x =1 so y = 90for B, x= 3 so y = 30par day work 1/90+1/30= 4/90so to complete the whole work time required 90/4 = 22 and 1/2

burogini.vinod
Profile Answers by burogini.vinod

Jan 20th, 2007

A=3B
B=A-60
B=3B-60
=>B=30
=>A=90
work division is 1/30+1/90=4/90
so,when they both work together 90/4

pravesh28
Profile Answers by pravesh28 Questions by pravesh28

Feb 26th, 2010

Answer 22.5 day
Let B complete the 1 part of job =1/x day
according 2 question.
3/x=1/x-60

Solving
x=90
B complete job=90 day
A complete the job=30 day

When both doing then
1/90+1/30
4/90
Complete the job
90/4= 22.5 day Answer.