2 hours after a freight train leaves Delhi a passenger train leaves the same station traveling in the same direction at an average speed of 16 km/hr. After traveling 4 hrs the passenger train overtakes the freight train. The average speed of the freight train was?A. 30B. 40C.58D. 60

None of the above. I get 10.67 km/h.The passenger train moves 64 km in 4 hours until it catches the freight train. If the freight train has a 2 hour head start, it moves 64 km in 6 hours, which is an average speed of 10.67 km/hLook at the question. If the passenger train is traveling at 16km/h and it catches the freight train, it must be moving faster.... but all the answers say the freight train is moving faster which cannot be correct.I think there's a type-o in this question

speed of the passenger train is 16 km/hr.................. (given)

Now the passenger train overtakes the freight train after 4 hrs, so the freight train by this time would have travelled for 6 hrs(2hrs+4hrs).since we know that passenger train starts after 2hrs.

therefore distance travelled by freight train in 6hrs = distance travelled by passenger train in 4hrs( as they meet)

x*6=16*4 6x=64

x=10.67 km/hr

therefore the speed of freight train is 10.67 km/hr

To Get the valid answer from the options the passenger train speed should be 60 kmph instead of 16kmph. than by calculating we get the frieght train speed as 40 kmph.

So option B is correct answer

shivani

Oct 25th, 2012

A. 30

Rajat jain

Aug 7th, 2013

yes all the above options are wrong...because if the freight train avg speed is more than pass train than it won't be possible that pass train over take freight train..

vivek

Jul 26th, 2014

40

karthi

Feb 11th, 2015

60

Rahul Raj

Aug 23rd, 2017

Let the Distance Covered by Freight train = Passenger Train = D kms Speed of Passenger Train = 60 km/hr Time taken by Passenger Train to Travel distance D = 4 Hrs Time taken by Freight Train to Travel Distance D = ( 4 + 2 ) = 6 Hrs Distance = Speed × Time Distance Freight = Speed Freight × Time Freight ........ (i) Distance Passenger = Speed Passenger × Time Passenger ........ (ii) Distance Freight = Distance Passenger ⇒ Speed Freight × Time Freight = Speed Passenger × Time Passenger ⇒ Speed Freight × 6 = 60 × 4 ⇒ Speed Freight = 40 km/hr

S N Kruthika

Aug 13th, 2018

30

Lakshya Pandya

Sep 9th, 2018

Since,Distance is same .
So, we can write as
D=S1*T1
D=S2*T2
S1*T1=S2*T2
2*x=16*(2+4)
2x=16*6
x=58.

Siddhant sharma

Aug 8th, 2019

Let the speed of the freight train be x km/hr speed of the passenger train is 16 km/hr.................. (given) Now the passenger train overtakes the freight train after 4 hrs, so the freight train by this time would have travelled for 6 hrs(2hrs+4hrs).since we know that passenger train starts after 2hrs. therefore distance travelled by freight train in 6hrs = distance travelled by passenger train in 4hrs( as they meet)
x-16*6=16*4
6x-96=64
x=160/4
x=40

## 2 hours after a freight train leaves Delhi a passenger train leaves the same station traveling in the same direction at an average speed of 16 km/hr. After traveling 4 hrs the passenger train overtakes the freight train. The average speed of the freight train was?A. 30B. 40C.58D. 60

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