A family X went for a vacationUnfortunately it rained for 13 days when they were there.but whehever it rained in the morniong ,they had a clear afternoon and vice versa.in all they enjoyed 11 mornings and 12 afternoons.how many days did they stay totally?

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Parthasarathy Bhaskar

  • Jul 27th, 2006
 

i guess it must be 24 days.....

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Parthasarathy Bhaskar

  • Jul 27th, 2006
 

obviously the family must have spent some additional no of days apart from the 13. days....lets say it rained it the morning a times.....and 13-a times in the afternoon....then 11-a=12-(13-a) then 11-a=5;so the family spent 13+5 =18 days totally

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Scott McGillivray

  • Jul 30th, 2006
 

Whenever it rains, it only rains half a day.... so look at this problem in half days.The family was rained on for 13 {half days}, but they also had 11 + 12 {half days} of sun.So, 13 + 11 + 12 = 36 half days = 18 days.

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arpita

  • Aug 1st, 2006
 

there r 13 days raining.

n 11 morning n 12 afternoons i.e. 11+12 = 23 times

but for 13 days its once so only 10 time sin one day so ie 1 morning n 1 afternoon so 5 days they went for both the time.

total days 13 days raining n 5 days without it.

13+ 5 = 18 days

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sunil kumar choubey

  • Oct 12th, 2006
 

now as we can see that rain is there for only 13 days

so acc to ques they have enjoyed 11 mornings nd 12 afternoon now 

 these days should contain those days in which they have enjoyed both

afternoon and morning now as in my view  they have enjoyed 5 days without rain so they are there for 18 days

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johncenaBEIT

  • Jan 4th, 2010
 

Since, it rained for 13 days means that family X has enjoyed 6 mornings & 7 afternoons(total 13). That means for remaining 10 sessions has been enjoyed by the family X in 5 days only(2 sessions a day).
SO, answer 13+5=18.

Family X was there for 18 days.

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sourav

  • Oct 9th, 2011
 

18days

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