amardeep rajpal

• Nov 10th, 2006

 

hi the answer to the series problem is definitely wrong it will be 132

as 3+7=10

 10*2=20

20+7=27

27*2=54

54+7=61

61*2=132

sananthya

 Profile 

• Nov 10th, 2006

 

Hi Frenz,Trying to help u a little frm my side.(1) 50 minutes ago it was 4 times ..... ( For complete one, refer the 2nd question frm Shakuntala Devi's Puzzles to puzzle you)Let the time from now(Z) to 6 pm be x minsThen from the question, time from 3pm(X1) to the time that was fifty mins ago(Y) = 4x minsConsider the below fig X1--------------------------------Y------------------------------Z-------------------------------X2 3pm <----4x-----> 50mins <-------x--------> 6pm 4x + 50 + x = 180==> 5x = 130 ; x = 26 mins(2) Odd man out.3 10 20 27 54 61 _ 3 10 20 27 54 61 _____ +7 *2 +7 *2 +7 (s/b *2)So the answer is 61 * 2 = 122 ( The previous reply was right, except that a small calc mistake was done with the answer )Hope the above solution is made clearer. I'm ready to solve any other questions to the extrent I can.Frenz, I'm preparing for my dream company. Please pray for my success.Good luck to all job seekers.My sincere suggestion, " Have confidence on you and have faith in God". If you believe that you have done your part well, then leave rest to God. Prayers do have answers but only if we are correct in our part.So good luck to all my dear friends.Regards,Sats

ashwani garg

• Nov 13th, 2006

 

 hiiiiiiiii dear

                 1 question is easy this is

                            diffrance bw 3'o clock &6=180

                    then divide the 3 hours in this maner =50+4x+x

                                   x is time for 6'oclock    

                                    then 50+4x+x=180

                                            5x=130

                                              x=26

kukuadventure

• Dec 5th, 2006

 

Hi,,,The ans for 1). Fifty minutes ago if it was four times as many minutes past three o,clock,how many minutes is it to six o,clock?sol:The trick to this is understanding the questn properly... the question often misleads most ppl...Thanks to shakuntala devi(puzzles 2 puzzle u page 1)U shud understand that 50 mins ago it was 4 times the mins (reuired to be 6 o'clock) past 3 o'clock.let x be the mins to 6 oclock.Now we know mins betn 3 to 6 are 180.These 180 would comprise of x+50+4x (as it was 4 times mins required to b 6)thrfore.. x+50+4x=180i.e 5x = 180-50=130x=130/5 = 26 mins

kk

• Dec 10th, 2006

 

answer for the fourth question is 3

solution:

first two trains meet after 2 1/2 hrs, then the second after 1 hrs then the third one after 1 hrs .. 

2 1/2+1+1=4 1/2hs

sunil choubey

• Jan 25th, 2007

 

the series is let a,b, then acc to it the next value is b+a+b-a

sivaramakrishna

• Jan 25th, 2007

 

hi the answer to the series problem will be 122 as 3+7=10 10*2=2020+7=2727*2=5454+7=6161*2=122

Harshavardhan

• Jan 30th, 2007

 

Consider all the Odd positioned number as one series and all the Even positioned numbers as another seriesEven Series: 10 27 61 (they can be written as 10 10+17*1(27) 27+17*2(61).....then ODD: 3 20 54 __ (it is similar to 3 3+17*1(20) 20+17*2 (54) 54+17*3(104)Ans: 104... better to go by the alternatives given for the problem...

ksbhat

 Profile Answers by ksbhat 

• Jan 31st, 2007

 

Ans to Q#4 would be this.............. Consider the 1st trains leave from both sides,viz, Bglr and Mdrs. Let us focus on the 1st train leaving from Bglr. [ train leaving from Bglr= Bglr train ; train leaving from Mdrs= Mdrs train] The 1st Bglr train, meets the 1st Mdrs train after 2.5hrs from the beginning.Now, the 2nd Mdrs train is 1 hr behind the 1st mdrs train,as it is given. So, 1st Bglr train meets the 2nd Mdrs train 0.5 hr after meeting the 1st Mdrs train.( Pls dont forget that even our 1st bglr train is moving) Hence 1st Bglr train meets the 2nd Mdrs train after 3 hrs from the beginning.The 3rd train will be 2hrs behind the 1st Mdrs train =>the 1st bglr train meets the 3rd Mdrs train (2hrs/2) after meeting the 1st mdrs train, i.e., after 3.5 hrs from the beginning.............Going on like this, we can form the following table: index of the Mdrs Train met Time elapsed from the beginning 1 2.5 hrs 2 3 hrs 3 3.5 hrs 4 4 hrs 5 4.5 hrs 6 5 hrsThe above table is w.r.t. the 1st Bglr train.Notice that this train meets the 6th Mdrs train( which will be starting towards Bglr) at its end point.Hence the 1st Bglr train meets 5 trains during its journey.( excluding the train whose start coincides with the end point of this train) If we go further...................The 2nd Bglr train meets 6 trains , the 3rd - 7 trains, the 4th- 8trains,the 5th and the rest all meet 9 trains. [ In all these cases the coinciding start and end point of a pair of trains, is not considered as meeting during the journey]So any train, other than the 1st 5 trains from either side, meets totally 9 trains during their journey.This is in my opinion. What do you all say?

keerthi

• Feb 24th, 2007

 

the answer is 122
3+7=10
10*2=20
20+7=27
27*2=54
54+7=61
61*2=122

Subhojeet

• Feb 25th, 2007

 

The starting train from either of the stations, will cross a minimum of six(6) trains till it comes to stop.

Shravan Kumar Talwar

• Feb 28th, 2007

 

The answer for the series is 122 and not 132!!!!!

Debashis

• Mar 6th, 2007

 

Dear Friend the solutioin you gave is absolutly correct
 But the answer will be ---->122
 as
          61*2=122

Eldhose

• Mar 7th, 2007

 

I feel the answers u all gave on the question on train are wrong.


Do you know why?

I will explain..

When a train start from the station another train is starting from the other station.
But u should think that , at intervals of 1 hr 5 trains are already on the track.
Now as one train starts from a station, one of the 5 trains already on the return track will reach the station. and u know that another train is there one hour distant from there, on the return track. This train will meet that train within half an hour. NOT one hour. Bcoz, this train is moving on the same speed as of the other one . That is speed doubles so, time taken is half.

Hope u understood this much.

Now we know, at each 30 mts interwal our train will meet another .

That is a total of 10 trains we will meet. PLUS we will meet one as we reach the station .

That means we will meet a total of 11 trains in the whole journey.


 You can mail ne if u have any doubts.

Thankz

p.Nagulsamy

• Mar 14th, 2007

 

The answer for series is 122 not 132

arjun

• Jun 25th, 2007

 

The answer is 122 frnd as 61*2 is 122

Japneet

• Oct 13th, 2007

 

The answer to the series problem would be definitely 122.
3+7=10
10*2=20
20+7=27
27*2=54
54+7=61
and
61*2=122

tapan sood

• Nov 20th, 2007

 

Dear
For that Trains  question When you are giving answer as 11 why are you counting those trains which are already on the same track....One train will not meet any train on same track when all trains are moving with same speed...So trains which one train will meet in whole journey will be on other parallel track.and those will be 3 as first train will be after 2.5 hours,next after one hour,and next one more hour.

nickyswetha

 Profile Answers by nickyswetha 

• May 23rd, 2008

 

3 10 20 27 54 61 _
ans .162

the answer is 122.

3

3+7 = 10
 
10+7+3 = 20

20+7 = 27

27+7+20 = 54

54 + 7 = 61

61 + 7 + 54 = 122

prasenjitm47

 Profile Answers by prasenjitm47 

• Nov 3rd, 2010

 

Answer for question no.4:-

                       Hour          Hour            Hour         Hour             Hour

Bangalore        1st            2nd             3rd            4th               5th                      Madras

                    Train A->

                  <-Train B

                                       Train C->

                                     <-Train D

                                                          Train E->

                                                         <-Train F

                                                                           Train G->

                                                                          <-Train H

                                                                                               Train I->

                                                                                               <-Train J

We consider the counting for Train A(Because we have assumed Train A at 1st Hour),then it is meeting with B,D,F,H,J.so the answer is 5.

 

priyamvad

 Profile Answers by priyamvad 

• Jun 10th, 2014

 

suppose the train from bangalore starts at 00.00 hrs , so it will reach chennai at 05.00 hrs. so It will meet all those trains from chennai which are in running condition between 00.00 to 5.00 hrs.

now the trains which are in running condition between this time(00.00 and 5.00 hrs (both inclusive )) will be those trains which started from chennai at -
19.00 hrs , 20.00 hrs , 21.00 hrs, 22.00 hrs, 23.00 hrs, 00.00 hrs , 01.00 hrs , 02.00 hrs, 03.00 hrs, 04.00 hrs and 05.00 hrs --> so total count is 11 trains.
if you ignore the boundary cases , i.e, the train just starting from bangalore at 00.00 will meet train reached and about to stop at bangalore at 00.00 , and the train about to stop at chennai at 05.00 hrs will meet the train about to start at chennai at 05.00 hrs.
Then the train will meet 9 trains.
But we should consider the boundary cases also , so the Correct answer should be 11 trains