Ashutosh Joshi

• May 16th, 2005

 

36

Dey

• Jul 16th, 2005

 

can u tell me how to reach the answer 

Palanisamy

• Aug 11th, 2005

 

Ans :33

NAVEEN

• Nov 19th, 2005

 

21

QL

• Mar 20th, 2006

 

3+(3+x)+(3+2x)+(3+3x)+(3+4x)+(3+5x)+fa'sage=186

x=168-fa'sage/15

x=5 fa'sage=93 the elder son=28

x=6 fa'sage=78 the elder son=33

x=7 fa'sage=63 the elder son=38

x connot >7

yuvaraj

• Mar 10th, 2007

 

Can you tell me how did you get ans 36

SudiSExy

 Profile Answers by SudiSExy 

• Sep 18th, 2008

 

As per me if 3*2 s the age of the younger son then at the regular intervals menas next ages will be 6*2,9*2,12*2,15*2,18*2 then total will be 126 years so elder sons age is 36 and the age of father is 60 years that makes 186 years

aranya.biswas

 Profile Answers by aranya.biswas 

• Feb 18th, 2010

 

The exact ans can be given if interval was given

any way

let fathers age=X

interval=N

therefore,

when 6th son born,

father's age=X+5N

1st son=5N

2nd son=4N

3rd son=3N

4th son=2N

5th son=N

TOTAL=X+20N

after 3 year total age increase=7*3=21

therefore,

X+20N+21=186

OR

X+20N=165

if N=9 then X= -15(can't be) so interval lesser than 9

if N=8 then X= 5(cant be) so interval lesser than 8

if N=7 then X= 25(may be) so interval 7 or lesser

thus

if interval =7 then elder son=5*(7)+3=38(NOW)