ck

• Apr 4th, 2005

 

61

prathibha

• May 17th, 2005

 

sorry number of handshake is 1770 butpeople is 885

niranjan

• Jun 3rd, 2005

 

For the condition specified there can never be 60 hand shakes

Chetan Arora

• Jul 15th, 2005

 

If the no of ppl are 'n' ttoal no of hand shakes are n-1 + n-2 + n-3 + ... + 3+ 2 + 1 
so the total hand shakes = [n(n+1)]/2 
here n = n-1 therefore total hansshakes  
[(n-1)(n-2)]/2=60 
this equation doesn't get satisfied so the question is wrong !!!

Palanisamy

• Aug 11th, 2005

 

Ans : n(n-1)=number of hand shakes 
 
where n is no. of persons. 
 
so qus. is qrong.

ravindra garg

 Profile Answers by ravindra garg 

• Nov 23rd, 2005

 

The Question is wrongIf the no of peoplel are 'n'Total hand shakes = [n(n+1)]/2 here n = n-1 therefore total hansshakes [(n-1)(n-2)]/2=60 this equation doesn't get satisfied

vineet saxena

• Apr 28th, 2006

 

there can never be 60 handshakes. so que is wrong.

pradeep

• Apr 17th, 2007

 

n(n+1)/2=60  should be yeild an integer value.
Answer is one greater than n.
But equation yeilds fractional value.

pragyan.anand

 Profile Answers by pragyan.anand 

• Jul 18th, 2008

 

selecting 2 people at a time from n people can be done in nc2 ways i.e.,n(n-1)/2 ways
                                     =>    n(n-1)/2=60
                                     =>     n is a rational value.......

aranya.biswas

 Profile Answers by aranya.biswas 

• Feb 18th, 2010

 

n*(n-1)/2=60 is eqn

but from this n is fractional

It is not possible.

Bhavin

• Jun 12th, 2013

 

number of person could be more than 8 .
Because in question they not mention like everyone "must" have to handshake with other.