sandeep

• Apr 19th, 2005

 

the probability is 1/8

Ashutosh Joshi

• May 17th, 2005

 

3/8

Amit

• Jul 5th, 2005

 

3/8

KIRAN

• Jul 29th, 2005

 

3/8

priya

• Sep 23rd, 2005

 

n(s)=8c3=56

n(E)=8c1=8

so probability=n(E)/n(s)=8/56

                                =1/7

rohith

• Feb 28th, 2006

 

3:3:2

mtgeek

• Mar 23rd, 2006

 

Probabality has to be 3/8, because his father picks 3 out of 8 to go to the zoo. You have a chance of 3 out of 8 to be in that group.

Vivekanand

• Jun 19th, 2007

 

The question is that one child getting selected by his father. So probability of selecting this guy is 1/8 and there are remaining 2 positions, for which he would pick by 8C2. The total no.of combinations are 8C3. So the probability is

             1/8 * 8C2            1/8 * 8*7/2                
            --------------    =    --------------------   =    1/16 = 0.066
                8C3                     8*7*6/3*2*1

Rachit Agrawal

• Jul 16th, 2007

 

Well Vivekanand made a small mistake. It should be

1. Select the child. And then out of & children there is 7C2 ways to select any two. So number of favorable chances are 7C2 * 1 = 21

2. Total number of cases are 8C3 = 56

so the Probability is 7C2/8C3 = 21/56 = 3/8

anish007

 Profile Answers by anish007 

• Jul 17th, 2007

 

probability is ((1/8)*(7C2))/(7C3)=3/40

geekavi

• Jul 24th, 2007

 

Obviously the probability would be 3/8

mayank goswami

• Aug 29th, 2007

 

the probability is 1/6!

Saurabh Shekhar

 Profile Answers by Saurabh Shekhar 

• Jun 12th, 2010

 

3c8*1c3=  1/168

Trinity

• May 9th, 2016

 

Is this compound or simple?