meera

• Jun 30th, 2006

 

cube has 12 sides, totally (6*4)+(4*8) cubes on the edges f it s 1*1*1 dimension. ie 58 cubes on the sides, which can take atleast 2 or more colored faces

ans:58

chaitanya

• Jul 9th, 2006

 

answer is 56 ,8 on edges and 48 on sides

Ankur Jain

• Jul 25th, 2006

 

The answer should b 56.

8 on corners + 4*12 on each edge.

venkataswami

• Jul 27th, 2006

 

ans: 56 (sure)

Scott McGillivray

• Jul 30th, 2006

 

I get 564 * 2 sided cubes per edge * 12 edges = 488 corner cubes48 + 8 = 56

sasidhar

• Jul 31st, 2006

 

hello venkataswami, can u explain clearly

chitra

• Aug 23rd, 2006

 

The formula for the cube prob is n^3=((n-2)^3)+6((n-2)^2)+12(n-2)+88--->3 sides painted12(n-2)--->2 sides painted6((n-2)^2)----> 1 side painted(n-2)^3-----> no sides paintedhere,atleast 2 sides shuld be paintedso, 2 side +3 side=48+8=56

surajit patra

• Nov 23rd, 2006

 

ans is 48becouse 6side is there and just (n-2)*12(6-2)*12=48

anjali

• Jan 2nd, 2007

 

on each corner edge 6 cubes,

4no corner edges x 6= 24

on each vertical (4)faces 8cubes  remaining faces top and bottom already covered

24+ 4x8 =56