A man was on his way to a marriage in a car with a constant speed. After 2 hours one of the tier is punctured and it took 10 minutes to replace it. After that they traveled with a speed of 30 miles/hr and reached the marriage 30 minutes late to the scheduled time. The driver told that they would be late by 15 minutes only if the 10 minutes was not waste. Find the distance between the two towns? Ans. is 120 bt could somebody plz tell the approach

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sanatdas2006

  • Feb 20th, 2006
 

the question is not presented correctly here.first case: if he drives with v ml/hr, then he reaches in T hr.second case: if drives with v ml/hr, stops after 2 hr and fixed tier in 1/6 hr and then drives at 30 ml/hr (drives for T-0.5-2-1/6), he reaches in T-0.5 hrthird case: if he drives with v ml/hr, stops after 2+1/6 hr (with counting time for fixing the tier) and then drives at 30 ml/hr (drives for T-0.25-2-1/6 hr), hr reaches in T-0.25 hreq 1 ---> L = v*Teq 2 ---> L = 2v + 30 (T+0.5 - 2-1/6)eq 3 ---> L = (2+1/6)v + 30 (T+0.25 - 2-1/6)subtract (3)-(2)0 = v/6 + 30(-0.25)v=45subsitute in (2)L = 90 +30(L/45 +0.5-2-1/6)L=120 miles

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