On a skating plane, Michel and Jennie are in a distance of a mile on each side of a point. They are going to skate to the direction of each other�s. Jennie, having added force with the flow of the wind, skated two and one-half miles faster than Michel and beat her 6 minutes. What are the times taken by both of them?

Interview Candidate
Dec 1st, 2005
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Sea Bass

Dec 2nd, 2005

d = rt, where d is distance, r is rate of speed, and t is time.For both skaters, distance = 1 mile.Given:Jennie: 1 = 2.5r(t - 6)Michel: 1 = rtFor Jennie's situation, solving for rate:r = d/t2.5r = 1/(t - 6) // using substitutionr = 1/2.5(t - 6) // divide by 2.5r = 1/(2.5t - 15) // Jennie's rate (in miles/minute)Next, substitute Jennie's rate for Michel's rate and solve for time:t = d/rt = 1/(1/(2.5t - 15)) // using substitutiont = 2.5t - 15 // from here on out, simplify equationt - 2.5t = -15 -1.5t = -15t = 10 // Michel's time (in minutes)Jennie's time is t -6, therefore:Jennie took 4 minutes and Michel took 10 minutes.

pallaviranib
Profile Answers by pallaviranib

Dec 8th, 2005

let michael speed=r, jennie=2.5r, distance d=1mile, r=speed in miles/hrt=time taken by michael in hrs, so time taken by jennie= t-(6/60)= t-0.11=rt1=2.5r(t-0.1)solving these, we get t= 1/6hr=10min. so time taken by michael is 10 min and by jennie is 4min