Meghraj Shah

• Aug 29th, 2005

 

the answer is 10mins

anandarao

 Profile Answers by anandarao 

• Dec 27th, 2005

 

man saved 20 min in total journey.i.e 10 min for onward journey.horse cort met man after 30 min of arrivel of plane. so plane came early by 40 min (30+10)

MAHAVEER PATIL

• Feb 3rd, 2006

 

if speed of horse cart and bike is same then plane has arrived 1/2 hour early than its scheduled arrival at airport

Harshil Joshi

• May 27th, 2006

 

Plane comes 20 min early than seduled because let assume plane's arrivel time is 2:40 and distance b/w home and airport is 40 min so, man starts at 2:00 and at 2:20 he reach at middle and plane arrive now at 2:30 he meet horce cart who has his airmail. Now, he come back at home at 3:00 but if plane will be on time than he will reach at airport at 2:40 and come back home at 3:20 so, this way he saves 20 min because of early arrival of plane

vamsy

• Jun 26th, 2006

 

ans:10min:::assume  he started at 1:00,so at 1:30 he met cart .He returned home at 2:00.so it took him 1 hour for the total jorney.by doing this he saved 20 min.so the actual time if the plane is not late is 1 hour and 20 min.so the actual time of plane is at 1:40.The cart travelled a time of 10 min before it met him.so the plane is 10 min early.

bhuvanbhoot

 Profile Answers by bhuvanbhoot 

• Jul 17th, 2006

 

plane arrived 10 mins early

for details contact via mail

rajitha

• Aug 11th, 2006

 

hi,

can u plz explain in detail how u got the ans...

thanks,

Rajitha.

devendra tapdia

• Aug 16th, 2006

 

Hi,

I think it should be 10 mins

(2:00pm) H------30mins------M-----A

(3:00pm)H------30mins------M-----A

so as it meets horse cart in middle and SAVES 20mins

so 20mins=2*(distance M to A requires time)

therefore M to A time=10mins

so it goes like

(2:00pm) H------30mins----->M(2:30pm)--->A(2:40pm)

(3:20pm)H<------30mins------M(2:50pm)<-----A(2:40pm)


that is we fulfill condition that is SAVES 20 mins.


As 1st case we reach home at 3:00pm


& 2st case we reach home at 3:20pm

sarat_619

 Profile Answers by sarat_619 

• May 18th, 2008

 

40 minutes

akshaygs21

 Profile Answers by akshaygs21 

• May 27th, 2008

 

Plane arrived 20 min early..
Assume speed of man is 60 km/hrs;
Distance between his house and airport is 40 km.
so he start at 1:40 and reach the airport at 2:20 so arrival time of plane is 2:20
After receiving his mail he returns to home at 3:00

Earlier case:
He left his home at 1:40
after 20 min means (after traveling 20 km) at 2:00 he is 20 km away from his home
same time plane arrives (means at 2:00) now distance between airport and man is 20 km.. so 10km is covered by man in 10 min and same by horse cart in 10 min and they meet at 2:10..and man return to home at 2:40 ((he saved 20 min)..


O-----------------------*-----------------------------------------------O
Airport--------------(man receive his mail)--------------------------man's house

jaismary

 Profile Answers by jaismary 

• Jun 5th, 2008

 

10min

jaismary

 Profile Answers by jaismary 

• Jun 5th, 2008

 

45

Abikumar

 Profile Answers by Abikumar 

• Oct 22nd, 2010

 

The answer is 10, since he saves 20 min, the distance covered is two(i.e) gone n come back........20/2=10

johnumman

 Profile Answers by johnumman Questions by johnumman

• Nov 10th, 2010

 

Ans : 20 mins

                                                      Early scenario
 1:00 >>>>>>>>>>>>>>>>>>>>>>>>>>> 1:30                                         1:20  
 2:00 <<<<<<<<<<<<<<<<<<<<<<<<<<<
(Home)------------------------------------------(Mid way)-------------------------------(Airport)
 1:00      >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>  1:40
 2:20    <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
                                                       Actual scenario