TCS Interview Question

(1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?
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Narmadeshwra Jha

  • Aug 25th, 2005
 

the answer is  
 
 
5/(n+5)

MAHAVEER PATIL

  • Feb 3rd, 2006
 

0.462

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YOGENDRA GUJAR

  • Feb 3rd, 2007
 

leaving the first numerater and last denominater, all the numerater and denominater will cancelled out one another. Ans. 5/(n+5)

bujjiec

  • Jul 23rd, 2009
 

1-1/6=5/6;1-1/7=6/7;........(1-(1/n+4))=(n+3)/(n+4);(1-(1/n+5))=(n+4)/(n+5);
there fore
(5/6)(6/7)........((n+3)/(n+4))((n+4)/(n+5))=5/(n+5)=1-(n/(n+5))

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Take n=5 for example, then above equation becomes 5/6*6/7*7/8*8/9*9/10=5/10.
Which implies all the term cancel except first numerator and last denominator, so in general 5/n+5
is the answer.

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Sapna

  • Apr 16th, 2012
 

The answer is zero because expression is (1-1/6)(1-1/7)........ 1-1=0 and 1-1/6=0 so (1-1/6)*(1-1/7).....=0

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Tejaswini

  • Jun 7th, 2019
 

Except first numerator and last denominator all other numerators and denominators will be cancelled. so ans is : 5/(n+5).....

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