thiyagarajanganesan

 Profile Answers by thiyagarajanganesan 

• Aug 12th, 2006

 

i dont know how to solve this question.plz give me the steps

Raghuram Reddy.K

• Dec 5th, 2006

 

at first time both carry laugage of 52 kgs, they pay $100 and $60 and second only been to abroad then he pay $ 340 160/x gives numver of kgs they carried extra. = y 160/x =y 160 = x*y then get the values for trial and error example 10*16 52 - 16 = 36 this is kgs allowed for both 36/2 is the kgs allowed for one ie 18

rems

• Dec 7th, 2006

 

hey!!!!

how this answer comes...

i am showing u another way,,,,,,just check it and reply

G1=extra leggage handled by Ganesh

S1=Extra by Shankar

N= Normal weight without charcge.....

For shankar,N+S1 Total weight

For Ganesh,N+G1

So total weight,N+S1+N+G1=52 Kgs

Money paid by Shankar for extra leggage is (Consider T as tax )=S1*T=100

For Ganesh,G1*T=60

If is taking By ganesh ,an additonal N will be added to him,So

(N+S1+G1)*T=340

From This NT=180.

Solving We get N=14.5

ubron

• Jan 11th, 2007

 

Let the minimum luggage any person can carry be x. Now 52kgs is = 2x plus the extra carried by ganesh(for which he pays 60$) and by Shankar(for which he pays 100$).The second part of the question says that had Ganesh carried the luggage all by himself it would have cost him an extra of 360$.He has been charged more because now he has to pay for Shankar's minimum luggage too(and that is 180$ ,360-(60+100) ). So the cost of x luggage is 180$. 60$ is 1/3rd of 180$ and 100$ is 5/9th of 180$.
So therefore 2x + (1/3)x+(5/9)x=52
                     x=18kgs