nitin

• Jun 26th, 2005

 

suppose the distance is a meter..and the speed of cycle is v and on feet u 
then 
2 x (2/3a)/v=(1/3a)/u 
v=4u 
four times..........

saritha

• Jul 1st, 2005

 

Suppose distance is d, 
cycling speed is v and foot speed is u 
 
then  
2*(2/3d)/v=(1/3d)/u 
=> v=4u 
So 4 times greater

Mohammad Asadullah

• Jul 18th, 2005

 

Let d = distance 
x = speed for cycling 
y = speed for walking 
 
Equation becomes: 
 
=> 2*(2d/3)/y=(1d/3)/z 
=> y/z=4

vids

• Jun 27th, 2006

 

let the total distance covered be x.

distance covered by cycling=2x/3

distance covered on feet=x-2x/3=x/3

time taken for cycling=t,for feet=2t,(here t represents the total time)

speed of cycling=2x/3/t=2x/3t

speed when on foot=x/3/2t=x/6t

therefore, 2x/3t*y=x/6t

i.e. y=1/4

therefore the speed by foot is 1/4 times less than that by cycling.

thus the speed of cycling is 4times more than that on foot.

Hassan

• Sep 20th, 2006

 

Its very simple to solve if we understand the situation.  The man covers twice the distance on cycle as he walks, in half the time he took to walk. Very obvious that it is 4 times. 

sravan_reddy001

 Profile Answers by sravan_reddy001 

• Jun 25th, 2008

 

let 2x be distance covered in cycling, then x is covered on foot,
walking x took twice the time as cycling 2x, (i,e)
there fore speed on cycling is 4 times that of feet.
but this is not the answer(not how many times, its how many times greater,
therefor 4x-x = 3x ==> its 3times greater..

keerthivasan

 Profile Answers by keerthivasan 

• Jul 22nd, 2008

 

2/3=2x/3x. So assume any value for x such as x=5.10/15 is covered by cycling in 'a'time.To cover the rest (i.e) 5 he take twice.So cycling speed is 4 times greater than feet.

cpgupta

 Profile Answers by cpgupta 

• Aug 2nd, 2008

 

speed of cycle is 4 times than speed during walk

deepak643

 Profile Answers by deepak643 

• Dec 26th, 2008

 

since a man travels 2/3 distance by cycle and 1/3 distance on foot  ......
he takes twice the time to travel on foot for the half the distance that he travelled on a cycle   so it wil be 4 times the time taken by him for travelling 1/3 distance

so ans zzz    1/4

MojesMak

 Profile Answers by MojesMak 

• Nov 21st, 2010

 

I guess this will make things easy!!
Let 'c' be the speed of cycling and 'f' be that of feet.
than by problem statement,
(2/3)c+(1/3)f = 2c
therfr, (1/3)f=2c-(2/3)c
therfr, (1/3)f=(4/3)c
therfr, f=4c (in terms of time taken)
since distance is same, the inverse gives, speed of cycling is four times that
of speed

Regards,
Mojes