george

• Sep 23rd, 2006

 

substitute the two values...ie, elapsed time after midnight in the eqn.here it will be 17 and 20find temp. and find the differencepercentage of rise or fall will bediff. of temp/temp. at 5pm*100

hemanth

• Oct 4th, 2006

 

replace 5 and 8 in place of t.

KANNAN.S

• Feb 14th, 2007

 

Hi friends,
For this question u must have to integrate that equation and apply 9 as upper limit and 4 as lower limit.
I am sure about that. All others are wrong.......

Navins

 Profile Answers by Navins 

• Sep 6th, 2007

 

Substitute 5 and 8 in the given equation
for 5 you will get 21
for 8 you will get 32
asked that percentage fall or rise in temper 21/32*100 this will be the answer i.e 65%

pravesh28

 Profile Answers by pravesh28 Questions by pravesh28

• Feb 27th, 2010

 

ans is 16 percent

let T eqals = -t^2/6+4*t+12 ( where t is elapsed time)

rate of change in temp. eqals dT/dt

dat is -4t^2-36t/(18+4*T)^2

here time elapsed is 3

putting the value t eqal 3

we get 144/900

so percentade change

(144/900)*100

ans 16 percent