Six persons A,B,C,D,E & F went to solider cinima. There are six conseutive seats. A sitsin one of the seats followed by B, followed by C and soon. If a taken one of the six seats ,then B should sit adjacent to A. C should sit adjacent A or B. D should sit adjacent to A, B,orC and soon. How many possibilities are there?

Questions by Madhusmita_behera

Showing Answers 1 - 8 of 8 Answers

Rekha

  • Nov 24th, 2006
 

10

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sandy

  • Nov 28th, 2006
 

hey rekha,

can i know how u got it.

my explanation is :

there are 6 places in total. among these 4 placestaken into consideration.

by going with the combination that is possible its 6C4

i.e, 6!/4! (2!)= 15.

ans is 15.

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azeem ahmed matte

  • Jan 30th, 2007
 

da answer is 32.i dunno hw to calculate it mathematically, bt if i try to solve is by writing down n giving 1st, 2nd, 3rd, till 6th position , thn whn A is at 1st position - 1 possibility2nd------------ 5 possiblity3rd------------- 10 "4th------------- 10 "5th------------- 5 "6th-------------- 1"so total is 1+5+10+10+5+1= 32

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Bhoomika sharma

  • Jan 3rd, 2009
 

lets make the possibilities:

If A sits first which is followed by B and the number of options or the ways in which B can sit around A is 2.
i.e. AB,BA

Now,if C wants to sit adjacent to A or B it can sit in 4 ways i.e. 2 ways each for sitting near A or B.

Now, again for D we have 8 ways i.e. 2 ways each to sit near A,B,orC.

Similarly, we can see for E we have 16 ways.

thus, F has total of around 32  ways to sit near A,B,C,D  by 32 ways.

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