ABCDE are sisters. Each of them gives 4 gifts and each receives 4 gifts No two sistersgive the same combination ( e.g. if A gives 4 gifts to B then no other sisters can give four toother one.)(i) B gives four to A.(ii) C gives 3 to E.How much did A,B,C,E give to D?

Questions by Madhusmita_behera

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ram

  • Oct 17th, 2006
 

this is kind of a tricKy question. therE can be only the following combinations

4-0

3-1

2-2

1-1-2

if the sisters don't repeat the combinations then only 4 of them could exchange gifts. the other sister need to use of the above combination to distribute the gifts.

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pkoshti

  • Feb 18th, 2007
 

 
B already given 4 to A So B will give 0 gift to D as only 4 gift can be given by each.

C will give 1 to D

Now Remaing are If A have given 2 gift to D
 Then E can give any one from 0 only

Or

If have E have given 2 to D then A will give 0 .

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marian.chandan

  • Mar 4th, 2007
 

it can b ny 1 of the following combinatons but whiich is correct.........

firstly v know tht B has given all 4 to A therefore it gives no gift to ny other sister......

now look at the combinations.........

A      C      E

4      0      0
3      0      1
2      0      2 
1      0      3 
0      0      4   
3      1      0    
2      1      1  
1      1      2   



now can ny1 suggest w/c is right??????????

i think data is insufficient.............

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Aravind

  • May 29th, 2007
 

As someone said it is a tricky question.  I think the answer is in the first part of the question.  It says "... and each receives 4 gifts".  It clearly says that each sister received only 4 gifts.  So, the answer to this question should be 4.  I don't see a need to really bother about any combinations here.

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tapandalal

  • Dec 22nd, 2010
 

Question is not how many gifts D received, question is who gave how many gifts to D.
If we see there is one more rule "If A gives 4 gifts to B then no other sisters can give four to other one" which means "No two sisters give the same combination"

Having said that, B can not give any gifts to any one as she gave 4  so it is out of the window and in addition no other sister can give 4 gifts to D

Now C has given 3 gifts to E so in that case no ther sisters can give 3 gifts to D also.

So now we have A, C and E in picture who can give gifts to D. Plus we can not chose 3 and 4 as our option.

Now if we select to give C to give one gift ( and C can give only one gift because she already gave 3 gifts to E)then A and E can not give one gift to D because no two sisters can have same pattern.

Same was if we select A to give 2 gifts then E can not give 2 because of "Not duplicate rule" and if E gives 1 and A gives 2 then also one gift is left and C can not do that with the same rule, so 

either data is insufficient or there has to ne a multiple choice and answer will be none of the above

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