A Hare & Tortoise have a race along a circle of 100 yards diameter. The tortoise goes in one direction and hare in another. The hare start after the tortoise has covered !/8 of its distance and that too liesurely. The hare and tortoise meet when the hare has covered only 1/6 of the distance. By what factor should the hare increse its speed so as to reach the end b4 the tortoise

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rukmini

  • Jun 11th, 2007
 

answer may be 24 times.

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rajivgupta1107

  • Dec 13th, 2007
 

I have some different answer as per the details:
Let the total circumference = x
Distance travelled by Tortoise with velocity V1 when
hare has not started = x/8----(1)
Distance covered by Hare  (with velocity V2) when they meet =x/6
Time taken by Hare = x/6.V2-------------------(2)

Distance covered by Tortoise in time x/6.V2 = V1 * (x/6.V2 ) = V1/V2  * (x/6)

Total distance travelled when they meet = x/8 + x/6 + V1/V2  * (x/6) = x
so 1/8 + 1/6 + V1/6V2 = 1

Sovling we get V1/V2=17/4


So ans is approximately 4.

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