A farmers wife says to her husband if we have 75 chicken ,they can be fed for 20 days and if still more 100 chicken are there they can be fed for only 15 days

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dilip

  • Apr 6th, 2006
 

hi help if one can,what is the approach to solve this question and is there any tricky way to this kind of problem..

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manohar

  • Apr 13th, 2006
 

300 chicks

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Sravya

  • May 13th, 2006
 

Hi All, Acc to me the answer must be 600. I have seen in many previous papers that the answer is 300 but culd not get that in any way. The approach i followed was: Assume that the number of chicken are : X Assume that the availabled feed is : y units Feed consumed by each chick in one day in first scenario is :( y/20)/(X-75) IIrly Feed consumed by each chick in one day in second scenario is :( y/15)/(X+100) equating these two we get X=600(Assuming that each hen eats the same amount of feed everyday)Regards,Sravya:)

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ashish

  • May 19th, 2006
 

hey i didnt got the question, all the data is given so what we have to find

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SIddharth Chauhan

  • Jun 30th, 2006
 

initially farmer has x no. of chikens and that last up to d days

Then food he want is = x*d

now he want to selll 75 chickens so x-75 no of chickens and food last up to 20 days more means d+20. still our initial food is the same = x*d.

now he want to buy chickens so x+100 of chickens and food last up to 15 days less means d-15. still our initial food is the same = x*d.

now two equations we get

 (x-75)*(d+20) =xd

 (x+100)*(d-15)=xd by solving we get x = 300 and d = 60

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