Harry

• Jan 31st, 2006

 

at first to place 1 , we have 6 choices. then to place 6 only one .

later to place 2 we have 4 choices and to place 5 only one.

finally to place 3 we have 2 choices and to place 4 only one.

so, total chances to arange them is 6*1*4*1*2*1= 48.

G@0

• Mar 2nd, 2006

 

In fact, I think there's only 2 combinations.

Plz remember a die is 3D symmetric, that makes it tricky.

Rajiv

• Apr 5th, 2006

 

Hi

Can you please elaborate how did u come to this conclusion that there are only 2 ways to arrange the combinations of 1-6,2-5,3-4

Sravya

• May 13th, 2006

 

Hi all, The answer should be 7. As specified in the question one combination is 1-6,2-5 and 3-4. Now fixing 1-6 the possible different combinations are 1-6,2-3,4-5 and 1-6,2-4,3-5 Now fixing 2-5 the possible different combinations are 2-5,1-3,4-6 and 2-5,1-4,2-6 Now fixing 3-4 the possible different combinations are 3-4,1-2,6-5 and 3-4,1-5,6-2. Since for a dice have 1-6 in opposite is same as having 6-1. Hope its clearThanks,Sravya:)