Ritesh

• Sep 6th, 2005

 

The answer should be 11.00  
 
The question is either wrong.. 50% speed means Extra speed with what it has

Nitin Rathod

• Oct 24th, 2005

 

Question: A bus started from bus stand 8.00am and after 30min staying at destination it returned back to the bus stand. The destination is 27 miles from the bus stand the speed of the bus 50percent fast speed at what time it returns to the bus stand.
Answer: 1.00am

sunitha.mocherla

• Dec 16th, 2005

 

answer 1.00pm

e.kaivhta

• Dec 26th, 2005

 

A bus started from bus stand 8.00am and 30min return the bus stand .Actually the bus return 1am

MAHAVEER PATIL

• Feb 3rd, 2006

 

assuming bus speed at 27miles / hr

Bus will reach destination at 9.00 am

and will start return journey at 9.30 am

To cover other 27miles at 50% slower speed i.e at 18miles /hr it will take 1hr 30 minutes and will reach at start point at 11am.

manoj

• Mar 23rd, 2006

 

data is insufficient

imran khan

• May 8th, 2006

 

answer:11:00 a.m

msaranyas

• Jun 14th, 2006

 

11.am

anupam007

 Profile Answers by anupam007 

• Jun 15th, 2006

 

11a.m

hariharan

• Jun 16th, 2006

 

can you say that how you calculated that the bus returns at 11a.m with a proper explanation please

srinu

• Aug 16th, 2006

 

Consider the speed of the bus is 50 percent faster in its return journey.

Eswara

• Sep 27th, 2006

 

Hai ,The question is correct, But they arer not denoted that the initial speed, The initial speed is 18km/hr.Now u will solve that the answer will come 11 am

Rameshsam

 Profile Answers by Rameshsam 

• Sep 6th, 2007

 

Hi Eswara,

As you denoted if you take the intial speed as 18 means you will get an and is 1:00 pm..
But you noted as 11:00 am.,
Can you explain me how you?got that?

santosh vr

• Sep 29th, 2007

 

Dist=27
Let ongoing speed=27m/hr
time=1hr
it reaches at 9:00
waits there upto 9:30
dist=27
speed=150%of 27
=54
time=27/54
=1/2hr=30min
it reaches home at 10:00