Bhavik R Domadia

• Sep 1st, 2005

 

4 is the answer

sriniu190

 Profile Answers by sriniu190 

• Nov 24th, 2005

 

Bhavik R Domadia Wrote: 4 is the answer

i  couldn't able to arrive at ur ans,

my steps:

n - distance b/w poles

N - no. of poles

1000/N   =n

1000/(N-1) = (5/3)n

final one => 2N = 5

  so pls explain ur solution.

email id: sriniu190@gmail.com

ganeshraj

• Nov 27th, 2005

 

hi

see if there are n poles thenthere are n-1 spaces in between them.

given data:

mtrs:1000 poles=n.    number of spaces=n-1

length of each space=1000/n-1.

now he said that a pole is taken out so there are n-1 poles and

therefore n-2 spaces

now according to him

1000/n-2=1000/n-1 + 5/3

now calculate the value of n it would be 22 or so.....

tmhasan7

 Profile Answers by tmhasan7 

• Sep 20th, 2006

 

SIMPLE.....

Step 1: Space between the two poles originally = 1000/(N-1) (If there are N poles there are N-1 Spaces)

Step 2: One pole is removed. So the no of poles is N-1 and no of spaces is N-2. It has been said that space reduces 2/3rd.  

There fore we get 

1000/(N-1) =(2/3)1000/(N-2)

(N-2)/(N-1)=2/3

3N-6=2N-2

N=4