x= banana on first day for five corresponding days x+x+6+x+12+x+18+x+24=100 5x+60=100 5x=40 x=8 first day=8 second day=x+6=8+6=14 third day=20 fourth day=26 fifth day=32

let the banana eaten by him on the first day be x. each day he is eating 6 more than the first day. so x+(x+6)+(x+12)+(x+18)+(x+24)=100. solving this we get x=8. there fore the number of banana eaten by him on the first day is 8.

let he eat (x-12) banana on first day then he will eat (x-6,x,x+6,x+12) on next four days then according to condition; x-12+x-6+x+x+6+x+12=100 5x=100 x=20 number of banana that he ate on first =20-12 =8

Answer is 8 as Consider the no of bananas he ate on day 1 as X; Then no of bananas on day2 - X+6 On day3 - X+6+6=X+12 On day 4 - X+18 & on day 5 - X+24 So the equation becomes X+(X+6)+(X+12)+(X+18)+(X+24)=100 5X+60=100 5X=100-60=40 x=40/5=8.

let the person eat x-12,x-6,x,x+6,x+12 in 5 days
then 5x=100
x=20
so first day will be 20-12 ie 8 ans.

Imdadul

Dec 10th, 2015

10

shaik.chand

Dec 17th, 2015

x+(x+6)+(x+12)+(x+18)+(x+24)=100
5x+60=100
5x=100-60
x=40/5
x=8.
so he ate daily 8 bananas

as

Jun 21st, 2016

8

Pintal

Jul 12th, 2016

8

priti

Jul 14th, 2016

100/5=20
avg of all term in AP middle term so,
1.2.3.4.5 the middle term=1+5/2=3 on third day he ate 20 bananas,
so 1 2 3 4 5
8 14 20 26 30
so on 1st day he ate 8 bananas

vinod raj

Jul 26th, 2016

On the first day he would have eaten 76 bananas
2nd day= 82 (76+6 more then the previous day)
3rd day = 88 (82 + 6 more than previous day)
4th day = (88 +6) 5th day (94 +6 == 100 reached)

Dharmishtha

Jul 28th, 2016

x+(x+6)+(x+12)+(x+18)+(x+24)=100
so now
6+12+18+24=60
then 100-60=40
40/5=8
so on the first day he eat 8 bananas
and so 8, 14,20,26,32=100

## A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?

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kuntal sarkarProfile Answers by kuntal sarkar Questions by kuntal sarkar

x+(x+6)+(x+12)+(x+18)+(x+24)=100

or, x=8

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