A software engineer starts from home at 3pm for evening walk. He walkspeed of 4kmph on level ground and then at a Speed of 3kmph on the uphill and then downhill at a speed of 6kmph to the level ground and then at a speed of 4kmph to the Home at 9pm.what is the distance on one way?

  • Interview Candidate
  • 1
  • 2727

Showing Answers 1 - 1 of 1 Answers

Vivek Sharma

  • Jun 14th, 2005
 

The above question can be solved in 3 ways: 
 
Approach 1: 
 
Let, the total time taken while travelling one way be: x 
then, 
time taken to travel back is given by: 6 - x 
We know that the distance travelled both the ways is same, therefore, 
3.5(x)=5(6-x) 
[ 3.5 = (4 + 3) / 2 = average speed while going upside. 5 is the average speed while coming back] 
solving for x we get, 
x = 3.5 
Therefore, 
distance travelled = 3.5 * 3.5 = 12.25 approx. 
Total dist. travelled = 12 * 2 = 24. 
 
2. Short Cut Method: 
 
We know that if a body travels a certain distance in x km/hr and then the same dist. again in y km/hr then, the average speed of the body is given by: 
2xy/x+y 
Applying the above formula we can get the total average speed of the man through out the journey. 
(2 * 3.5 * 5) / (3.5 + 5.0) = 35 / 8.5 = 4.11 aprox. 
total time taken to complete the journey = 9 - 3 = 6 hrs. 
therefore,  
total distance traveled = 4 * 6 = 24. 
one way distance = 24 / 2 = 12

  Was this answer useful?  Yes

Give your answer:

If you think the above answer is not correct, Please select a reason and add your answer below.

 

Related Answered Questions

 

Related Open Questions