There are 3 societies a, b, and c. A lent tractors to B and C as many as they had. After some time B gave as many tractors to A and C as many as they have. After sometime c did the same thing. At the end of this transaction each one of them had 24. Find the tractors each originally had.

A had 39, B had 21, C had 12,
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ankit aggarwal

  • Sep 29th, 2006
 

how  this  can  be  possible

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TCE CSE GUYS(Coimbatore)

  • Jun 1st, 2007
 

Answer is very simple.

Proceed from the back.

finally all of them had 24 tractors.


A       B      C
24     24    24
12     12    48
06     42    24
39     21    12

FIRST STEP

A=24/2=12
B=24/2=12
C=24+12+12=48

SIMILARLY TILL THE END.

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kishore DS

  • Jun 7th, 2007
 

Hi There,

Please explain me the answer briefly as it is little bit confusing.

Regards,
Kishore DS

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