Both guptha and sinhas have two young sons whose ages are under eleven. the names of the boys, whose ages round off to the nearest year are all different, are rajesh , praveen, lalitm and pratap. Taking the ages of the boys only to the nearest year, the following statements are true.Rajesh is three years younger than his brother isPraveen is the oldest.Lalit is half as old as one of the gupta boys.Pratap is five years older than the younger sinha boy.The total ages of the boys in each family differ by the same amount today as they did five yeasrs ago.How old is each boy, and what is each boys family name ?

Showing Answers 1 - 6 of 6 Answers

HariHaran N

  • Sep 7th, 2005
 

Guptha: 
Pratap-10 
Rajesh-7 
Sinhas: 
Praveen-9 
Lalitm-5

  Was this answer useful?  Yes

Varun

  • Oct 30th, 2005
 

How is the above solution possible when it is mentioned

praveen is the oldest.............

i think answer is:

Sinha's

Rajesh : 2

Lalit    : 5

Gupta's

Praveen : 10

Pratap   :  7 

  Was this answer useful?  Yes

Nishant Joshi

  • Nov 25th, 2005
 

From given condition it is easy 2 find out which son belongs 2 which family

Gupta             Sinha

Praveen-10      Lalit-5

Pratap  -7       Rajesh-2     (5-3)

  Was this answer useful?  Yes

Give your answer:

If you think the above answer is not correct, Please select a reason and add your answer below.

 

Related Answered Questions

 

Related Open Questions