The size of a program is N. And the memoryoccupied by the program is given by M = square root of 100N. If the size of the program is increased by 1%then how much memory now occupied ?

Plz any one tell me,how to answer this....

This question is related to TCS Interview

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Oct 6th, 2006
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kr vanitha

Oct 10th, 2006

plz i need to answer that question thank u

vchandm23
Profile Answers by vchandm23

Oct 10th, 2006

here M= sqrt(100N)
1N+100N=101N%
sqrt(101N)/10

Mithila

Nov 22nd, 2006

M=sqrt(100N)
N is increased by 1%
therefore new value of N=N + (N/100)
=101N/100
M=sqrt(100 * (101N/100) )
Hence ,we get
M=sqrt(101 * N)

priyat
Profile Answers by priyat

Feb 17th, 2008

0.2 is the ans

chandradeepika
Profile Answers by chandradeepika Questions by chandradeepika

May 28th, 2008

M1=sqrt(S1)=sqrt(100N)
S2=101%S1=1.01N
M2=sqrt(S2)=sqrt(100*(1.01N))=sqrt(101N)
% increase is :
= (((sqrt(101N)-sqrt(100N))/sqrt(100N))*100)
=(((sqrt(101)-10)/10)*100)%
=((10*sqrt(101))-100)%
=((10*10.05)-100)%
=(100.5-100)%
=0.5%