The colors on the two sides were different and no two cards had the same color combination. When the cards were distributed to them, they kept their cards on the table with one side per card facing up, of course. Each cardholder knew the color of the hidden side of his card. They spoke up one by one as follows:A: My card, showing Red above,has either Green or Blue color beneathB: My card, showing Green above,has neither Green nor Blue colorbeneathC: My card, showing Yellow above,has either Blue or Yellow colorbeneathD: My card, showing Blue above,has either Blue or Yellow color beneathHowever, later it was found that exactly two of them were lying. Can you find who was lying and what were the colors on the hidden sides of each card? What is the correct answer & pls mention the solving procedure.

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barani

  • Jun 13th, 2006
 

C and D can lie as same color is not possible on both sides and the other possibility makes their cards having same color combination of blue and yellow. the possibility is A red -blue B green-yellow C yellow-red D blue-green

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Prathyusha

  • Jun 16th, 2006
 

The answer for this question is of Course there is a chance for C and D to lie since there cannot be 2 colors same on either side of the card.So C and D lie.

The possible combination for all of them is as follows:

A  red - blue

B  green - yellow

C  Yellow - red

D  blue - green

Let us think that no color repeats.If that is the case the answer would probably be the right answer.

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