A plane travels 695km with wind and 498km aginst the wind in same time.The speed of wind is 21km/hr. Find the speed of plane?

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saisreelu

  • Mar 8th, 2006
 

distance = speed * time

=>distance/speed = time.

let the speed of plane = x km/hr

695/21+x = time travelled with the wind......(1)

498/21-x = time travelled against the wind.....(2)

(1) and (2) are given to be the same..so..

695/21+x = 498/21-x.

Solving for x, we get

x ~= 3.46 km/hr.

Difficult to believe that a plane travels so slow! :)

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sriram krishnamoorthi

  • Mar 29th, 2006
 

ans. is 147.477 km/hr

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mrbene

  • Apr 7th, 2006
 

695 km, 498 km21 km/h197 km of 'wind effect', 98.5 km per directly, 4.69 hours (at 21 km/h). 596.5 km of plane travel in each direction, over 4.69 hours, 127.18 km/h as base speed. Plane travels 695 KM in 4.69 hours at 148.18 km/h, then 498 KM in 4.69 hours at 106.18 km/h.

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Abhinav Babel

  • Apr 12th, 2006
 

Shreelaxmi Your mathod was correct but your answer is wrong

the correct answer is 127.17 Km/hr

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anurag agarwal

  • Apr 28th, 2006
 

The correct answer is 127.17259kmh

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venugopal

  • Aug 3rd, 2006
 

sreelaxmi -'s method

answer is 1193/197

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sowjanya

  • Sep 20th, 2006
 

according to the information given in problem,the equation can be obtained as follows.

695/(x+21)=498(x-21)

By solving the above eqution we get x=127.172 Km/hr.

satya1288

  • Jan 20th, 2008
 

x1=distance travelled by plane with wind (695Km)
x2=distance travelled by plane against wind (498Km)

v1=velocity of plane with wind
v2=velocity of plane against wind
w =velocity of d wind (21Kmph)
v=velocity of d plane

given,      t1=t2
          => x1 / v1 = x2 / v2
          => 695/v+21 = 498/v-21
          => 685/498   = v+21/v-21
          =>1193/197  = v/21
          =>v = (1193*21)/197

      Hence, v=127.1725Kmph

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