Ramesh sit around a round table with some other men. He has one rupee more than his right person and this person in turn has 1 rupee more than the person to his right and so on, Ramesh decided to give 1 rupee to his right & he in turn 2 rupees to his right and 3 rupees to his right & so on. This process went on till a person has \\\'no money\\\' to give to his right. At this time he has 4 times the money to his right person. How many men are there along with Rameshand what is the money with poorest fellow.

Interview Candidate
Dec 22nd, 2005
1
1126

Showing Answers 1 - 1 of 1 Answers

praveen

Jan 13th, 2006

Here is the solution :Let us suppose there are n no of people and intially ramesh has L amount hence going in right direction of ramesh distribution of sum ll be Ramesh Lhis Right L-1...Last Person L-(n-1)After first round distribution of amonut from Ramesh to right Ramesh L +n-1his right L-1 -1next L-2 -1...Last L-(n-1) -1it is clear from data that last person ll be out of money first .Let us suppose this happens after k rounds Hence distribution of amont after k rounds Ramesh L + k(n-1)his right L-1 -k....Last person L-(n-1) -k also given that L + k(n-1) = 4(L-1-k)and L-(n-1)-k=0 (last person has 0 money )solving these two eqution we ll have n =7/(3-k)now as n and k are +ive and whole no hence only one sloutionn=7 k=2 hence L=8 Hence there are 8 persons and Poorest person after 2 rounds ll be second last person with some = L-(n-2)-k=1