Char foo(){char result[100]);strcpy(result,"anything is good");return(result);}void main(){char j;j=foo()printf("%s",j);}

Interview Candidate
Jun 19th, 2005
1
2378

First
Prev
Next
Last

Showing Answers 1 - 1 of 1 Answers

ramana

Jul 19th, 2006

'j' in main method will be pointing to an address in foo()'s stack. You might get "anything is good" in this case but there is no guarantee. In large programs, the address might be overwritten by something else and the result will be garbage. One should avoid returning pointers to stack addresses.