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Data Structures declared as Volatile and Const
What does it mean when a data structure is declared volatile? What does it mean when a data structure is declared Const?
pvsola
- Apr 3rd, 2008
Volatile - you are asking compiler to not to optimise the data structure as well as to reload to CPU registers whenever it is in use. Not a good idea for Data structure, will waste lot of CPU time in loading long data structures.
as_hmr
- Mar 11th, 2008
If we declare a data structure const means after declration that data structure is read only.Declaring a data structure Volatile is a order to compiler not to perform optimization on that data structure.
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Data Structure - character that repeats itself
Given a string of characters (let us say there are about 100 characters or more in the string), what is the most efficient method to use for finding out the character that repeats itself the most?Is it possible for us to use some kind of data structure for this?, if this is so,which is the best one that needs to be used?
vinod148
- Oct 23rd, 2009
There is no way for less that O(n) solution as we have to traverse the string atleast once.By traversing only once we can find the solutionKeep another variable which tracks the current highest occured character.
pvsola
- Apr 3rd, 2008
There is an way to solve this issue with complexity of O(n).1. MAke an array size of 2562. Using each charater read from the string as an index incremented the counter ...
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Which statement is true? A. Functions are declared in header files B. Functions are defined in header files
pvsola
- Mar 15th, 2008
Both statements are true, functions can be declared and defined in header file, but not a good practice.
Vijay K
- Sep 5th, 2007
A. is true.void fun(int); -> This is declaring a function.void fun(int a) -> This is defining a function.{....}
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printf("Address of j=%un",&j);
printf("Address of k=%un",&k);
return 0;
}
Suppose the answer is:
Address of i=2004
Address of j=2002
Address of k=2000
why is the address decreasing ?">Consider the following program:#includemain(){int i=3;int *j;int **k;j=&i;k=&j;printf("Address of i=%un",&i);printf("Address of j=%un",&j);printf("Address of k=%un",&k);return 0;}Suppose the answer is:Address of i=2004Address of j=2002Address of k=2000why is the address decreasing ?
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*ptr++;
printf("%sn",ptr);
ptr++;
printf("%sn",ptr);
}
explain difference between *ptr++ and ptr++">Find the output for the following C programmain(){char *ptr = "Ramco Systems";*ptr++;printf("%sn",ptr);ptr++;printf("%sn",ptr);}explain difference between *ptr++ and ptr++
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If the following program (myprog) is run from the command line as myprog 1 2 3, What would be the output? main(int argc, char *argv[]) { int i,j=0; for(i=0;i<argc;i++) j=j+ atoi(argv[i]); printf("%d",j); }
A) 1 2 3B) 6C) errorD) "123"
vanavill
- Mar 7th, 2008
initially J=0,then, it incremented by the arg value one. now it is 1.then it incremented by the arg&nb...
