If the following program (myprog) is run from the command line as myprog 1 2 3, What would be the output? main(int argc, char *argv[]) { int i,j=0; for(i=0;i<argc;i++) j=j+ atoi(argv[i]); printf("%d",j); }

A) 1 2 3
B) 6
C) error
D) "123"

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Dec 10th, 2005
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bhaskarsinghal
Profile Answers by bhaskarsinghal

Jan 2nd, 2006

ans B)6

pvsola
Profile Answers by pvsola

Mar 6th, 2008

ans: 6

Explanation: converting string "c:myprog.exe 123" to integer will return 0

vanavill
Profile Answers by vanavill

Mar 7th, 2008

   initially J=0,then, it incremented by the arg value one. now it is 1.then it incremented
by the arg value 2. now the value of J is 3. then it's value incremented by the arg value 3. now it's value is 6.now,the loop condition over. The J=6.

        so the answer is 6.