Print number of distinct characters in a string.

How do I implement a C program that reads a string and prints a table with the number of occurrences of each character in the string.
Ex: Rubber. r = 2, u = 1, b = 2, e = 1.

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Nov 23rd, 2011
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Answer

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jbode
Profile Answers by jbode Questions by jbode

Aug 31st, 2012

Simple, fairly brain-dead example. Assumes any input characters fall into the range [0...CHAR_MAX).

Code
#include <stdio.h>


#include <ctype.h>


#include <limits.h>


 


int main(int argc, char **argv)


{


  int counts[CHAR_MAX] = {0};


  char *p;


  int i;


 


  if (argc < 2)


  {


    fprintf(stderr, "USAGE: %s <string>


", argv[0]);


    return 0;


  }


 


  for(p = argv[1]; *p != 0; p++)


    counts[(size_t) *p]++;


 


  for (i = 0; i < CHAR_MAX; i++)


  {


    if (counts[i] > 0)


    {


      if (isprint(i))


      {


        printf("%c: %02d


", i, counts[i]);


      }


      else


      {


        printf("%x: %02d


", i, counts[i]);


      }


    }


  }


}

shweta gupta
Profile Answers by shweta gupta

Jun 25th, 2014

Code
 


int main()


 


{


 


char str[11]="aabcadefge";


int a[26];


for(int i=0;i<26;i++) a[i]=0;


int couner=0;


for(int i=0;str[i]!=;i++){


        a[(str[i]-a)]+=1;


}