nutan

• May 21st, 2005

 

Max 52 matches will be played as there are 51 teams go on dividing with 2 + 1 to find the solution or add 1 to number of team

Monty

• Jul 19th, 2005

 

i guess 52 is the answer if its a knock out tournament but for a doubly eliminating process we should have a total of 100 matches to be played for one to emerge as the winner. coz to eliminate 1 team we need 2 matches to be played n to eliminate 50 teams we need 100 matches..is that right??

G

• Aug 5th, 2005

 

n = number of teams 
ans = (n * 2) - 1 
= 51*2-1 
=101 
 
got the ans by trying out 2 teams and then 3 teams. The least number of matches would be 100. But max is 101. Any takes on this?

raj

• Aug 6th, 2005

 

 
the answer 101 is correct, it is n + (n-1) , in this case n is 51. Here is the explanation: 
 
say it is like a playoff tournament (each team is allowed to enter next round if it wins) then between 2 teams to decide a winner we play 1 game, if there are 3 teams we need to play 2 games, if it is 4 teams then 3 games and so on...  
 
but since here it is two losses that disqualifies a team, and we are considering the maximum possible (worst case scenario) ,  
if there are 2 teams and each team wins 1 game, then the third game is the decider, similarly if there are 3 teams, allow each team to play with all the other teams once first (3 games, which means 3 wins and 3 loses) lets assume each team 1 game and lost 1 (this results in the worst case scenario again) and during the second iteration, two games are enough ( 2 wins, 2 loses) and we have a winner here .... 
 
hence the final answer is n + (n-1)

Nithin

• Jun 25th, 2007

 

The part of the question which says that "" the team which loses 2 matches will b disqualified"" is just an eye wash...... don't consider that part .... all they asked was   how many matches will be played ????
so the answer should be 255.. for example .. consider there are 11 teams ..
so the total matches played by 11 teams would be 55...

 so when it comes to 51 teams tha answer should be  255

sachinspatil

 Profile Answers by sachinspatil 

• Jul 9th, 2009

 

Formula to get answer is (n*(n-1))/2

First take a simple example where n=3, n-1=2
(n*(n-1))/2
3*2/2
=3

Here,
n=51
n-1=50
51*50/2
=1275

In this question, the sentence, "If one team loses two matches, it will be
disqualified" is used only for making confusion/eyewash.

manojthesingham

 Profile Answers by manojthesingham 

• Dec 4th, 2009

 

Case 1:teams:2

 AvsB A wins B 

 AvsB B struggles for not to eliminated and wins A

 AvsB A/B has chance to be eliminated

Case 2:teams:3

 AvsB A wins B

 AvsC A wins C

 BvsC B/C eliminated, suppose B is eliminated

 AvsB B struggles for to be eliminated and wins A

 AvsB A/B has chances to be eliminated

Therefore I conclude tat if there are n teams then there are n + (n-1) chances