After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 years

49a

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  • 1973

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SRIVATSA V

  • Jul 22nd, 2006
 

let x and y be the current age of A and B respectivelybefore 10 years B's age=y-10 ans hence A's age after 10 years = x+10ie (x+10)=2(y-10)and x-y=9 (given)solving we get y=39 and 10 years later B's age=49

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naveenrajpeter

  • Jul 18th, 2007
 

a=2(b-20)
a-b=9
9+b=2b-40
49=b
afetr ten year 59.

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arunmacs

  • Jul 30th, 2008
 

A=2(B-10)

 A~B =9   if A>B then A-B=9

            A=2(B-10) =2(A-9-10)
ie., A=38 and B=29. (After 10 Years), B=19. (Before 10 Years)

 if B>A then B-A=9            A=2(B-10) =2(A+9-10) ie., A=2 and B=11, , B=1. (Before 10 Years)
 

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