Kayalvizhi

• Oct 3rd, 2006

 

Let a, b, and c denote pencil, pen and eraser respectively.

Given that the cost of one pencil, two pens and four erasers is Rs.22

This can be written as,

        a + 2b + 4c = 22 ..........(1)

Similarly, the cost of 5 pencils, 4 pens and 2 erasers is Rs. 32

This implies ....

        5a + 4B + 2c = 32 ......... (2)

Adding (1) and (2), we get

        6a + 6b + 6c = 54

We need to find the value of 3a + 3b + 3c.

Dividing by 2, we get

        3a + 3b + 3c = 27.

Hence, the cost of 3 pencils, 3 pens, and 3 erasers is Rs.27

     

sreeramdesikan

 Profile Answers by sreeramdesikan 

• Jul 16th, 2008

 

Rs.27
Add both the equation and divide the result by 2...

pranoti

 Profile Answers by pranoti 

• Jan 30th, 2011

 

Let cost of 1 pencil, 1 pen and 1 eraser be x,y,z.
now, x+2y+4z=22 - (1)
5x+4y+2z=32 - (2)
subtracting (2)-(1);
4x+2y-2z=10 or 2x+y-z=5 -(3)
subtracting (2)-(3);
3x+3y+3z=27
Answer=Rs27

prititripathi

 Profile Answers by prititripathi 

• Mar 7th, 2011

 

x+2y+4z=22

5x+4y+2z=32

add bth d eq. we get

6x+6y+6z=54

so 3x+3y+3z=27

Amit Kumar

• Sep 26th, 2018

 

15 rubbers cost ₹10.50.how many rubbers can be bought for ₹70? What will be the cost of 35 rubbers