Renuka

• May 30th, 2006

 

I think my answer will be 2 gallon of fuel consumed while coming.

the fuel consumed while going = X + (1/4)X

the fuel consumed while coming = X

the fule consumed for the trip = X+((1/4)X)+X = 4.5

Therefore the fuel consumed while coming = 2 gallon

Tell me, if I am wrong.

Punita

• Jul 9th, 2006

 

In the question, it is said that while going, 1/4 gallon more is consumed and not 1/4 th more oil of the oil consumed..So ur equation X+(1/4*X) will be incorrect.It will actually be X+1/4 while going..

prasad.telagamsetti

 Profile Answers by prasad.telagamsetti 

• Sep 30th, 2007

 

2 is correct answre ,,,,,,,,,,  boz,,,,, x+(x+x/4)=4 1/2;   x(2+1/4)=9/2   ; x(9/4)=9/2   ;x=2; it is correct

sriram_v

 Profile Answers by sriram_v 

• Aug 11th, 2010

 

here x+x+1/4 = 4 1/2, then 2x+1/4=9/2,

then 2x=9/2-1/4,

2x=17/4, x=17/8, x=2.125

very imp

 for coming up

2.125+ 1/4,

so 2.125+0.25=2.375

the correct ans is 2.375

sriram_v

 Profile Answers by sriram_v 

• Aug 11th, 2010

 

2.125 is not the right answer

 we need to add 1/4 to that to get the fuel consumed while coming up

the right ans is 2.125+0.25=2.375

Nirmal

• Aug 7th, 2019

 

total fuel=4.5 gallons
let amount of fuel for coming=x so a.t.q amonut of fuel for going = x+ x/4=5x/4.
so 5x/4+x<=4.5(as this is not mention that all the fuel is spent during the trip.)
so 9x<=18, x<=2 gallons