vijay

• Jun 25th, 2006

 

He is 11 km East away from the starting point

ABHISHEK LAKHOTIYA

• Jul 1st, 2006

 

near about 12 km  or (121+25)^1/2 km

veeramanikandan

• Jul 12th, 2006

 

  from a starting point he/she travels 3km east and 5km north. so 6km(root(5^2+3^2)) far from northeast. plus 8km is 14 km notheast from the starting point.

Milan Agarwal

• Sep 22nd, 2006

 

12 Kms is corect ans. n abishek hs given right justification,draw it in form of quadrants n u will get d soln.

VENUMAHADEVREDDY

• Oct 2nd, 2006

 

if u draw a rectangle of length of total(3+8) km and breadth 5km and draw a diagonal from the starting to ending point, by Pythagaros Theorem, square(hyp)=square(the both sides)

Therefore, 25+121=sqrt(answer)

it comes to be 12.083km

shivani

• Oct 4th, 2006

 

I saw the same question in 2 tcs papers. But they gave 13 as ans.But i dont know how.

ranjit

• Nov 6th, 2006

 

well the answer is 11.40 km east from he started..

(5^2+11^2)^1/2 = (23+121)^1/2

                  =11.40km..

Ramesh

• Feb 12th, 2007

 

3 km east .... 35 km north .... 58 km east .... 8Total ... 16 kmSubtract 3 km from 16 kmAnswer 13 km.