sindhujaumapathy

• Apr 4th, 2006

 

Hi,

The test input could be

          - 2,0(low boundary +1 or  -1)

         - any value on the boundary

         -1000.00,999.98(upper boundary +1,-1)

Regards,

Sindhujaumapthy

Prakash

• Apr 5th, 2006

 

Please let me know How will you test the decimal point on the boundary values

example

0.99999999 to -1.9234992939

Thanks

Prakash

Sandeep Patil

• Apr 6th, 2006

 

Test data

Input : Expected Result

Test for lower boundary 1

-0.99 : Reject

1 : Accept

1.01 : Accept

Test for higher boundary 999.99

999.98 (-0.01) : Accept

999.99 : Accept

10000 (+0.01): Reject

Here i choose -/+ by 0.01 becouse user can give input in two decimal points.

If you have dought that SUT may accept 999.991 you can even test for three decimal values.

Boundry value analysis we use to see wether SUT works fine at its boundary conditions or not.

shivanibehere

 Profile Answers by shivanibehere Questions by shivanibehere

• May 10th, 2006

 

This condintion is depend on the other condiotion here tester can test from 1-999

1) 1-1=0

2)=1

3)1+1=2

4)999-1=998

5)999

6)999+1=1000

raja.raja

 Profile 

• Oct 2nd, 2006

 

BVA"

min=1, max= 999.99

min-1=0-test case fail, max-1=998.99 test case pass

min+1=2 test case pass, max+1=1000.99test case fail

Akash Deep

• Aug 22nd, 2007

 

There is a misconception with boundry value analysis & most of comments were effected with it.

BVA applies -1 & +1 but one for each boundry.

example :
Range = 1 - 999.99
the correct Boundry Values for the given scenario :
-0.99,1,999.99,1000