Cricket Score Aptitude Question

If sachin score 76more than ahzar , and azhar and robin scores sum is 94 and azhar scores 76 less than
dravid and dravid score 26 more than robin . What was the total score done in match.
This question is related to Accenture Interview

Showing Answers 1 - 44 of 44 Answers

Pankaj Shinde

  • Mar 27th, 2006
 

Sachin=Azhar + 76 eq.(1), Azhar + Robin= 94 eq. (2), Dravid= Azhar+76 eq.(3) Dravid = Robin + 26 eq. (4).

Adding eq. (3) and (4). we get

2Dravid = Azhar + Robin + 102 eq. (5). Putting eq. (2) in eq. (5) we get

2Dravid = 94+102 = 196

So. Dravid = 196/2= 98.

Now solving one by one equatin we get. Sachin=98, Robin=72, Azhar=22, Darvid=98.

Adding their scores we get 290 as total score.

Guest

  • Jul 12th, 2006
 

    Equations:

     Azar = x runs

     Sachin = x + 76 runs

     X + robin = 94

     Dravid = x + 76 = 26 + robin

     x + 76 = 26 +(94-x)

     that means x = 22;

    so we get, Azar = 22, sachin = 98, robin = 72, dravid = 98,

    Therefore total runs = 290 runs  

karthik g

  • Jul 21st, 2006
 

we have the equations S=A+76----------1

                               A+R=94 -----------2

                              A=D-76----------3    or   D=A+76

                              D=R+26-----------4

from eq 1 and 3 we get        D=S

from eq 3 and 4      we get       R=A+50----------5

but    A+R=94(eq 2)

therefore       A+(A+50)=94    (since  eq   5)

A=22,R=72

D=S=A+76=R+26=98

therefore  D+S+R+A=98+98+72+22=290

Rahul varma k

  • Jul 31st, 2006
 

the answer is correct

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deepa j

  • Aug 8th, 2006
 

sachin=s, azhar=a, robin=r,dravid=d

given: s=76+a

         a+r=94

         a=d-76

          d=r+26

so take equation a=d-76 put " d value as r+26"

then a=r-50 substitute in a+r=94

so r-50+r=94

2r=144

r=72

thus a+r=94, we get a=22

then a=d-76 we get d=98

thus s=98

then total=s+r+d+a=98+72+98+22=290

pitambernitk

  • Aug 13th, 2006
 

let azhar score be x.

& robin score be y.

according to question,

score of sachin=x+76

score of dravid =y+26--------(1)

& also score of dravid= x+76---------(2)

since

eqn (1)&(2) is equal

y+26=x+76

=> y-x=50-----------(3)

since given

x+y=94-------------(4)

solving (3) &(4)

x=22, y=72

score of sachin=98

score of dravid=98

score of azhar=22

score of robin=72

total=290

rajarajan

  • Aug 13th, 2006
 

the correct answer cannot be given unless they specify the no of balls or overs the players played... or unless we know the scores of other players of the game... if no other players contributed scores.. and if the other team is all out for a duck then the score will be 290 in that match

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himaja

  • Sep 2nd, 2006
 

the final score is 290

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khader

  • Sep 5th, 2006
 

Sachin

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murali

  • Sep 5th, 2006
 

answer for the above question is 290

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kapil sharma

  • Sep 13th, 2006
 

ANSWER CAN NOT FIND, UNTIL IT IZ NT MENTION THAT IN MATCH ONLY THESE ABOVE BATSMAN CAME TO BAT

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balaganesh k

  • Nov 5th, 2006
 

hi,

       Simpliciter approach.

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sumit.manchanda

  • Mar 2nd, 2007
 

let azhar score =x
 robin score =y

x+y= 94             .............................1

dravid score is 76 more then azhar(or azhar score 76 less then dravid)
: x+76

draid score is 26 greater then robin: y+26

hence  x+76= y+26

  x-y = -50  ..............................................2

from eq 1 & 2 we get

x= 22 , y=72

azhar score =22   robin score = 72
dravid score = 22+76= 98

sachin svcore = dravid score = 98

total score =98+98+22+72= 290

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rahulsahu

  • Jun 4th, 2008
 

290
sachin=s;
azahr=a;
dravid=d;
robin=r;
s=a+76--------(1
a+r=94---------(2
a=d-76---------(3
26+r=d---------(4
solve the equations 3&4 then result will be appear ...
s=98
r=72
d=98
a=22
total=290

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given azar(a) ,sachin(s),robin(r),dravid(d)


a+76=s---------1
a+r=94---------------2
r+26=d------------3
d-76=a ----------4

frm 4 we get d=a+76-------5
solve 3 n 5
we get r=72
put r=72 in 2 we get a=22
put a=22 in 4 we get d=98 n s=98

total score in match is 209

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sabinva

  • Jul 9th, 2011
 

S=sachin,a=azhar,r=robin,d=dravid
s=76+a
d=76+a
a+r=94
r=d-26
 =76+a-26
substitute r in a+r=26
a+76+a-26=94
2a+50=94
a=22
Substituin the value of a
we get
 s=98
d=98
r=72

So the total score is 98+98+72+22=290

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Hassan Farooqi

  • Jul 18th, 2011
 

Mathematically it should be 290. However logically it can be any number over 290. We need to add the following 1) Extras 2) Scores of other batsmen 3) scores of the other inning (remember it is a test match)

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abhimanyu singh

  • Jul 25th, 2011
 


given;-
a + 76 = s
a + r = 94
a + 76 = d
r + 26 = d


total score made all player=a + r + s + d
=94 + a + 76 + r + 26 ( given a+r=94 and s=a+76 and d=r+26)
=196 + a + r
=196 + 94
= 290

Rohit Borse

  • Aug 5th, 2011
 

280

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rahul chandak

  • Aug 14th, 2011
 

290

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Shouvik Mitra

  • Aug 24th, 2011
 

Azhar+Robin=94;....eq 1
Dravid=Azhar+76;...eq 2
Sachin=Azhar+76;....eq 3
Dravid=Robin+26;...eq 4
Now eq 12 and eq 4 are combined
Azhar+76=Robin+26;
Robin-Azhar=76-26;
or, Robin-Azhar=50;...eq 5
From eq 1 we get,
Azhar=94-Robin;...eq 6
Putting eq 6 in eq 5 we get,
Robin-94+Robin=50;
or,2Robin=50+94=144;
or.Robin=144/2=72;
so,Azhar=94-72=22;
Dravid=76+22=98;
Sachin=98;
So,total score is=98+98+72+22=290;

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kapil

  • Aug 26th, 2011
 

Total score 290
Azhar score 22
Robin score 72
Dravid score 98
Sachin score 98

Example Azhar+robin=(22+72)=94
Dravid=Robin +26=(72+26)=98
Sachin=Azhar+76=(22+76)=98

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kamaljeet kumar

  • Aug 28th, 2011
 

290

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