A contribution of Rs. 500 was raisedfrom 500 people. The fee was as follows: Men: Rs.3.00 eachWomen: Rs. 2.00 eachChildern: 0.48 eachIf number of women is more than number of men, how many childern are there?

Two equations are
3x+2y+0.48z=500
x+y+z=500
solving we get
y=(6500-63x)/38 under y>x
very difficult to solve
give alternative way

Questions by pankaj_ismd

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Rathi

  • Apr 4th, 2006
 

solution:

let no of men as m, women as w and children as c.

3m+2w+0.48c=500  ----- I equation

m+w+c=500  -------II equation

solve I and II, get

1.52c=500+m, put least possible values for c and m, so that condition satisfy

try c=350 and m=32.

use this values in equ II, get w=118.

now check ur equ I, it will satisfy.

Therefore ans is  men=32, women=118, children=350.

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