I lost Rs.68 in two races. My second race loss is Rs.6 more than
the first race. My friend lost Rs.4 more than me in the second race.
What is the amount lost by my friend in the second race?

Suppose first race loss is x Rs. Then second race loss is 6Rs. more than first so... it is x+6Rs.
Sum of those two races - x+x+6 = 68 we solve it we get value of x is 31.
My friend lost 4Rs. more than my second race so it is 37+4=41 Ans is 41

First Race=x
Second Race= x+6
Total = Rs. 68
x+(x+6)=68
2x+6=68
2x=68-6
2x=62
x=62/2
x=31
First race=Rs. 31
Second race= 31+6= Rs. 37
4 more in second race= 37+4= Rs. 41

Mahesh poojary

Jun 19th, 2017

He lost in first race Rs.31
then second race he lost Rs.6 more than first race(31+6=37)
Totally he lost in second race Rs.37
then his friend lost Rs.4 more than his in second race(37+4=41)
totally his friend lost in second race Rs.41

## I lost Rs.68 in two races. My second race loss is Rs.6 more than the first race. My friend lost Rs.4 more than me in the second race. What is the amount lost by my friend in the second race?

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murali922Profile Answers by murali922 Questions by murali922

Ans : 41

first race loss = x

second race loss = y

Cond 1 : x+y = 68

Cond 2 : y = x + 6

Simultaneous eq. needs to be solved.

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